short LUA help please

[Roadrunner]

hi all,

 

if possible, i would like to know, how i can compare flags to flags using LUA, couldnt find it in search, maybe wrong key words, and dont want to get into MIST.

 

pseudo code:

 

Flag 1 != Flag 6
&&
Flag 2 != Flag 7
&&
Flag 3 != Flag 8
&&
Flag 4 != Flag 9
&&
Flag 5 != 1;

sadly no Flag unequal flag trigger option in ME :(

 

thanks,

RR

[Wrecking Crew]

Well, you can test if two flag do equal, and use that result. I can think of a couple appraoches.

 

Set two flags equal and when they are no longer return True.

 

Test if one flag goes true while the other is still false and return True.

 

...

 

WC

[Roadrunner]

i can as well, but not knowing how to "talk" with the flags via LUA is my problem, and my search didnt turn up something there :(

[Wrecking Crew]

Here's a way to display flag values.

 

===

Displaying Flag Values With Text Messages

 

Use a Do Script Action (does not require Mist) -

local msg = {}

msg[#msg + 1]='Blue All Points Flag 10000 value = '

msg[#msg + 1]=trigger.misc.getUserFlag('10000')

msg[#msg + 1]='. \n'

msg[#msg + 1]='Blue Vehicles In Zone Points Flag 20000 value = '

msg[#msg + 1]=trigger.misc.getUserFlag('20000')

msg[#msg + 1]='. \n'

msg[#msg + 1]='. \n'

msg[#msg + 1]='Blue Aircraft Points Flag 50000 value = '

msg[#msg + 1]=trigger.misc.getUserFlag('50000')

msg[#msg + 1]='. \n'

msg[#msg + 1]='Blue Heli Points Flag 60000 value = '

msg[#msg + 1]=trigger.misc.getUserFlag('60000')

msg[#msg + 1]='. \n'

msg[#msg + 1]='Blue Vehicle Points Flag 70000 value = '

msg[#msg + 1]=trigger.misc.getUserFlag('70000')

msg[#msg + 1]='. \n'

msg[#msg + 1]='Blue Ship Points Flag 80000 value = '

msg[#msg + 1]=trigger.misc.getUserFlag('80000')

msg[#msg + 1]='. \n'

msg[#msg + 1]='\n'

msg[#msg + 1]='Press Pause to freeze the action. \n'

trigger.action.outText(table.concat(msg), 6)

 

 

 

 

local msg = {}

msg[#msg + 1]='Flag 1 value = '

msg[#msg + 1]=trigger.misc.getUserFlag('1')

msg[#msg + 1]='. \n'

msg[#msg + 1]='Flag 2 value = '

msg[#msg + 1]=trigger.misc.getUserFlag('2')

msg[#msg + 1]='. \n'

msg[#msg + 1]='. \n'

trigger.action.outText(table.concat(msg), 6)

 

 

 

===

 

There's is the Witchcraft tool to help debug LUA scripts.

 

WC

[Grimes]

if trigger.misc.getUserFlag('1') ~= trigger.misc.getUserFlag('6') and trigger.misc.getUserFlag('2') ~= trigger.misc.getUserFlag('7') then

return true

end

 

As for flag unequal, yeah it doesn't directly exist. Could use 2 Flag is More than Flag conditions checked as an 'or' statement because if a flag is more than another they cannot be equal.