Thats ignoring aerodynamic effects. Which at 130knts will be quite large. Fly straight and level at 130knts, apply full brake and then nose down to maintain speed. Then fly 130knots on idle throttle - what nose down angle do you need? Compare.. That generates a rough calculation of the drag produced by the airbrakes.
Even really crappy brakes can lock a wheel - and the A-10 has anti-skid, so, pretty much by definition, the A-10 brakes can lock a wheel.
Good brakes can absorb the kinetic energy of the aircraft and convert that into heat, and can do that for a long time. Crappy brakes can only do that for a short amount of time - so you "run out of brakes".
In general, for a given mass sitting on rubber on tarmac = ~1g static friction (again, ignoring aerodynamic effects including lift).
So assuming the wings are producing zero lift (a little unlikely though, given the 20deg of flap) you can do 1g.... however, as stated, some lift = less downforce on tyres = less stopping force. Dynamic friction (a locked tyre sliding over tarmac) results in about 0.7g.
From this, assuming the wings are producing some lift, at the beginning of your landing roll you'll have not much downforce on the wheels. Therefor you'll produce proportionally less wheel braking (and it will require *much* less braking force in the cockpit to lock wheels).
At you roll out (and slow), more weight comes onto the wheels, and more wheel braking can be generated, and it requires more braking force in the cockpit to lock a wheel.
Antiskid would help hide the variable braking force required to lock wheels during the landing roll.
So the question for the devs - does A-10 model the force of the wheels on the tarmac, including lift generated by the wings, and does it use that in braking calculations for the aircraft?