JTAC decimal coordinates?

[Xxx]

Just purchased the Mirage, what a beauty!:thumbup:

 

I was wondering if there is a way of getting the JTAC coordinates in decimal lat/long, instead of MRGS?

 

Using JTAC with our LGB's is a superb feature, however MRGS is only useful in the Hog.

 

I have tried a conversion calculator, but it just gives errors at the MRGS entry?

 

With our INS waypoint system the JTAC is an interesting feature to add in the mission planner.

 

Regards,

David

[The_Tau]

Well when u convert MRGS to lat/long you propably get degress(°)/minutes(')/seconds('') format. M2k uses degrees/minutes/decimal seconds format so what u need to do is type in INS degrees/minutes and then take 2 first digits of seconds('') from classic lat/long and divide it by 60 to get decimal of it and type that in the end into INS.

[ALF7]

use mod nato.lua.rar

 

Sound\speech

 

п.с.save defolt

 

[Xxx]

Thanks guys.

[SilentSierra]

+1 Thanks. ED must add this fix to the DCS. This can be considered a cheat in servers with integrity check enabled.

[laumaya]

+1 Thanks. ED must add this fix to the DCS

[Frederf]

As a workaround you can use the F10 map as a MGRS to L/L converter, mouse cursor and the cycle units command. Seconds to fractions of a minute is quite easy 18+-3'' is 0.3+-0.05'. Tenth of a minute is plenty accurate for LGB delivery and/or finding the target visually.

[laumaya]

Seconds to fractions of a minute is quite easy 18+-3'' is 0.3+-0.05'.

 

Sorry, it's not clear for me. can you give me an example.:helpsmilie:

[Ramsay]

Sorry, it's not clear for me. can you give me an example.:helpsmilie:

 

60" (seconds) = 1' (minute)

 

18"/60 = 0.3'

 

3"/60 = 0.05'

 

though I tend to use: divide by 6, then divide by 10 when doing it in my head,

 

so: 18"/6 = 3 -> 3/10 = 0.3'

 

Frederf's calculations showed +/- 3" is a 0.05' difference (1853m x 0.05 = 93m) and calculating to the nearest tenth of a minute (+/-3"=+/-93 m=+/-304 ft) is sufficient to find a target or drop a LGB.

 

So:

 

20"/6 = 3.3 but we'd round to the nearest decimal i.e. 3 before dividing by 10 -> 3/10=0.3'

Edited November 2, 2017 by Ramsay

[laumaya]

60" (seconds) = 1' (minute)

 

18"/60 = 0.3'

 

3"/60 = 0.05'

 

though I tend to use: divide by 6, then divide by 10 when doing it in my head,

 

so: 18"/6 = 3 -> 3/10 = 0.3'

 

Frederf's calculations showed +/- 3" is a 0.05' difference (1853m x 0.05 = 93m) and calculating to the nearest tenth of a minute (+/-3"=+/-93 m=+/-304 ft) is sufficient to find a target or drop a LGB.

 

So:

 

20"/6 = 3.3 but we'd round to the nearest decimal i.e. 3 before dividing by 10 -> 3/10=0.3'

 

Now it's clear for me :book:

 

Thanks you