rweaves6 Posted November 15, 2017 Posted November 15, 2017 With all this presumption I thought I would run some real calculations in an attempt to provide a realistic prediction of the release time frame: ΠN(x1,…,xn,xn+ Therefore, the F-14 Module will be released when it is released. :thumbup: :unsure: [sIGPIC][/sIGPIC]
rjetster1 Posted November 15, 2017 Posted November 15, 2017 Whatever the release schedule is, there is a lot in the pipeline... it will be enough to keep us busy for a very long time to come. Waiting is tough, but it will be worth the wait!
swither Posted November 15, 2017 Posted November 15, 2017 Do u have some insider info about how far along the F14 artwork is? :O All we have been show is the placeholder textures (apart from a few pics of specific parts) Blacklion / Nick is one of our testers and advisors. /Daniel Heatblur Simulations
Kayos Posted November 15, 2017 Posted November 15, 2017 Blacklion / Nick is one of our testers and advisors. Lets hope that means before the end of the year then. Bring on the TOMCAT !!!! [sIGPIC][/sIGPIC]
ebabil Posted November 15, 2017 Posted November 15, 2017 Blacklion / Nick is one of our testers and advisors. aren't you also an insider? :) tell us something FC3 | UH-1 | Mi-8 | A-10C II | F/A-18 | Ka-50 III | F-14 | F-16 | AH-64 | Mi-24 | F-5 | F-15E| F-4| Tornado Persian Gulf | Nevada | Syria | NS-430 | Supercarrier // Wishlist: CH-53 | UH-60 Youtube MS FFB2 - TM Warthog - CH Pro Pedals - Trackir 5
Paradox Posted November 15, 2017 Posted November 15, 2017 aren't you also an insider? :) tell us something I think "insider" is understating it...
_schepper_ Posted November 15, 2017 Posted November 15, 2017 With all this presumption I thought I would run some real calculations in an attempt to provide a realistic prediction of the release time frame: ΠN(x1,…,xn,xn+1)Π−1N(t1,…,tn)=11−xn+1(x1,…,xn),=(2t1,…,2tn,∥t∥2−1)∥t∥2+1. ΠN(x1,…,xn,xn+1)=11−xn+1(x1,…,xn),ΠN−1(t1,…,tn)=(2t1,…,2tn,‖t‖2−1)‖t‖2+1. In these coordinates, the induced (round) metric on the unit sphere is well-known (and easily checked) to be conformally-Euclidean: g(t)=4(dt21+⋯+dt2n)(∥t∥2+1)2. g(t)=4(dt12+⋯+dtn2)(‖t‖2+1)2. Stereographic projection from the north pole (0,…,0,r)(0,…,0,r) of Sn®Sn® is given by the scaled mapping x↦t=rΠN(x/r)x↦t=rΠN(x/r), whose inverse is t↦x=rΠ−1N(t/r)t↦x=rΠN−1(t/r), i.e., rΠN(x1/r,…,xn/r,xn+1/r)rΠ−1N(t1/r,…,tn/r)=1r−xn+1(x1,…,xn),=(2t1,…,2tn,r(∥t/r∥2−1))∥t/r∥2+1. rΠN(x1/r,…,xn/r,xn+1/r)=1r−xn+1(x1,…,xn),rΠN−1(t1/r,…,tn/r)=(2t1,…,2tn,r(‖t/r‖2−1))‖t/r‖2+1. The induced metric in these coordinates is consequently r2g(t/r)=4(dt21+⋯+dt2n)(∥t/r∥2+1)2=4r4(dt21+⋯+dt2n)(∥t∥2+r2)2. Therefore, the F-14 Module will be released when it is released. If i calculate this right.... the outcome = in 2 weeks ---------------------------------------------------------- i7 2600K oc 4.7g / asus gtx 1080 gaming x+ / 16gig ram / ssd 500gig / oculus rift / jetseat se / saitek rudder ((next upgrade)mfg crosswind) / logitech warthog hotas + 20cm extention
firmek Posted November 15, 2017 Posted November 15, 2017 If i calculate this right.... the outcome = in 2 weeks You've almost got it wright. You need to apply the Banach fixed-point theorem to arrive to a fixed release date. Once you do it, the result is: 2 weeks from now + sqrt( (it's released when it's released)^2) - sqrt(x^2) just to avoid a miscalculation when it had been already released ;) F/A-18, F-16, F-14, M-2000C, A-10C, AV-8B, AJS-37 Viggen, F-5E-3, F-86F, MiG-21bis, MiG-15bis, L-39 Albatros, C-101 Aviojet, P-51D, Spitfire LF Mk. IX, Bf 109 4-K, UH-1H, Mi-8, Ka-50, NTTR, Normandy, Persian Gulf... and not enough time to fully enjoy it all
Robert31178 Posted November 15, 2017 Posted November 15, 2017 (edited) And here I was thinking that it was just an English Comp multiple choice test question. The answer naturally being: C: "It will be released." Just sit tight. Edited November 15, 2017 by Robert31178
paura19 Posted November 15, 2017 Posted November 15, 2017 (edited) April 2018 :smilewink: Remember autumn 2015 that Leatherneck want to show us 2 new modules. No offense:) Edited November 15, 2017 by paura19 MB2 Czech DCS server. Youtube české Tutorialy Discord MB2 1.Flight | =UVP= Czech school of TOP GUN | DCS at Airshow - Aviaticka Pout 4K player | ASUS B760-F | i7 13700KF 5,4Ghz | MSI 4080 SUPRIME X | 64Gb G.Skill 6000MHz | 2TB M2.PCIe4 for DCS | Corsair RM1000e | (build 2023)
Top Jockey Posted November 15, 2017 Posted November 15, 2017 With all this presumption I thought I would run some real calculations in an attempt to provide a realistic prediction of the release time frame: ΠN(x1,…,xn,xn+1)Π−1N(t1,…,tn)=11−xn+1(x1,…,xn),=(2t1,…,2tn,∥t∥2−1)∥t∥2+1. ΠN(x1,…,xn,xn+1)=11−xn+1(x1,…,xn),ΠN−1(t1,…,tn)=(2t1,…,2tn,‖t‖2−1)‖t‖2+1. In these coordinates, the induced (round) metric on the unit sphere is well-known (and easily checked) to be conformally-Euclidean: g(t)=4(dt21+⋯+dt2n)(∥t∥2+1)2. g(t)=4(dt12+⋯+dtn2)(‖t‖2+1)2. Stereographic projection from the north pole (0,…,0,r)(0,…,0,r) of Sn®Sn® is given by the scaled mapping x↦t=rΠN(x/r)x↦t=rΠN(x/r), whose inverse is t↦x=rΠ−1N(t/r)t↦x=rΠN−1(t/r), i.e., rΠN(x1/r,…,xn/r,xn+1/r)rΠ−1N(t1/r,…,tn/r)=1r−xn+1(x1,…,xn),=(2t1,…,2tn,r(∥t/r∥2−1))∥t/r∥2+1. rΠN(x1/r,…,xn/r,xn+1/r)=1r−xn+1(x1,…,xn),rΠN−1(t1/r,…,tn/r)=(2t1,…,2tn,r(‖t/r‖2−1))‖t/r‖2+1. The induced metric in these coordinates is consequently r2g(t/r)=4(dt21+⋯+dt2n)(∥t/r∥2+1)2=4r4(dt21+⋯+dt2n)(∥t∥2+r2)2. Therefore, the F-14 Module will be released when it is released. :thumbup: Exactly - that's precisely the same result I got ! Jets Helis Maps FC 3 JA 37 Ka-50 Caucasus F-14 A/B MiG-23 Mi-8 MTV2 Nevada F-16 C MiG-29 F/A-18 C Mirage III E MiG-21 bis Mirage 2000 C i7-4790 K , 16 GB DDR3 , GTX 1660 Ti 6GB , Samsung 860 QVO 1TB
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