After noticing this behaviour, I can't really wrap my head around the physics involved.
Here's the deal, when you are flying straight and level and turn with both cyclic and rudder, you eventually begin to ascend when in the turn.
Now, I would expect the aircraft to drop because you are increasing your force vector in the direction of the turn so the resulting vector from all the forces would lead to a decrease in lift vector.
I am wrong however, as I need to drop collective when in a turn with the Mi-8.
Can anyone explain?
From the FAA site:
As the angle of bank increases, the total lift force is tilted more toward the horizontal, thus causing the rate of turn to increase because more lift is acting horizontally. Since the resultant lifting force acts more horizontally, the effect of lift acting vertically is deceased. To compensate for this decreased vertical lift, the angle of attack of the rotor blades must be increased in order to maintain altitude. The steeper the angle of bank, the greater the angle of attack of the rotor blades required to maintain altitude. Thus, with an increase in bank and a greater angle of attack, the resultant lifting force increases and the rate of turn is faster.